(18+2x)(24+2x)=952

Solution for (18+2x)(24+2x)=952 equation:

(18+2x)(24+2x)=952

We move all terms to the left:

(18+2x)(24+2x)-(952)=0

We add all the numbers together, and all the variables

(2x+18)(2x+24)-952=0

We multiply parentheses ..

(+4x^2+48x+36x+432)-952=0

We get rid of parentheses

4x^2+48x+36x+432-952=0

We add all the numbers together, and all the variables

4x^2+84x-520=0

a = 4; b = 84; c = -520;
Δ = b2-4ac
Δ = 842-4·4·(-520)
Δ = 15376
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{15376}=124$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(84)-124}{2*4}=\frac{-208}{8}
=-26
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(84)+124}{2*4}=\frac{40}{8}
=5
$