(17x+23)=(8x-4)+(3x+17)

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Solution for (17x+23)=(8x-4)+(3x+17) equation: 



(17x+23)=(8x-4)+(3x+17)

We move all terms to the left:

(17x+23)-((8x-4)+(3x+17))=0

We get rid of parentheses

17x-((8x-4)+(3x+17))+23=0



We calculate terms in parentheses: -((8x-4)+(3x+17)), so:

(8x-4)+(3x+17)

We get rid of parentheses

8x+3x-4+17

We add all the numbers together, and all the variables

11x+13

Back to the equation:

-(11x+13)



We get rid of parentheses

17x-11x-13+23=0

We add all the numbers together, and all the variables

6x+10=0

We move all terms containing x to the left, all other terms to the right

6x=-10

x=-10/6

x=-1+2/3

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