2(3x+1)=10-(x+5)

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Solution for 2(3x+1)=10-(x+5) equation: 



2(3x+1)=10-(x+5)

We move all terms to the left:

2(3x+1)-(10-(x+5))=0

We multiply parentheses

6x-(10-(x+5))+2=0



We calculate terms in parentheses: -(10-(x+5)), so:

10-(x+5)

determiningTheFunctionDomain
-(x+5)+10

We get rid of parentheses

-x-5+10

We add all the numbers together, and all the variables

-1x+5

Back to the equation:

-(-1x+5)



We get rid of parentheses

6x+1x-5+2=0

We add all the numbers together, and all the variables

7x-3=0

We move all terms containing x to the left, all other terms to the right

7x=3

x=3/7

x=3/7

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