(17-3x)/4=(5x-11)/2

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Solution for (17-3x)/4=(5x-11)/2 equation: 



(17-3x)/4=(5x-11)/2

We move all terms to the left:

(17-3x)/4-((5x-11)/2)=0

We add all the numbers together, and all the variables

(-3x+17)/4-((5x-11)/2)=0

We calculate fractions


(-3x)/()+(-((5x-11)*4)/()=0



We calculate terms in parentheses: +(-((5x-11)*4)/(), so:

-((5x-11)*4)/(

We multiply all the terms by the denominator


-((5x-11)*4)



We calculate terms in parentheses: -((5x-11)*4), so:

(5x-11)*4

We multiply parentheses

20x-44

Back to the equation:

-(20x-44)



We get rid of parentheses

-20x+44

Back to the equation:

+(-20x+44)



We get rid of parentheses

(-3x)/()-20x+44=0

We multiply all the terms by the denominator


(-3x)-20x*()+44*()=0

We add all the numbers together, and all the variables

(-3x)-20x*()=0

We get rid of parentheses

-3x-20x*()=0

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