3+(2y+4)=48

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Solution for 3+(2y+4)=48 equation: 



3+(2y+4)=48

We move all terms to the left:

3+(2y+4)-(48)=0

We add all the numbers together, and all the variables

(2y+4)-45=0

We get rid of parentheses

2y+4-45=0

We add all the numbers together, and all the variables

2y-41=0

We move all terms containing y to the left, all other terms to the right

2y=41

y=41/2

y=20+1/2

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