(16x-7)+(8x+2)=(10x-19)

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Solution for (16x-7)+(8x+2)=(10x-19) equation: 



(16x-7)+(8x+2)=(10x-19)

We move all terms to the left:

(16x-7)+(8x+2)-((10x-19))=0

We get rid of parentheses

16x+8x-((10x-19))-7+2=0



We calculate terms in parentheses: -((10x-19)), so:

(10x-19)

We get rid of parentheses

10x-19

Back to the equation:

-(10x-19)



We add all the numbers together, and all the variables

24x-(10x-19)-5=0

We get rid of parentheses

24x-10x+19-5=0

We add all the numbers together, and all the variables

14x+14=0

We move all terms containing x to the left, all other terms to the right

14x=-14

x=-14/14

x=-1

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