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12(7x+5)x=13
We move all terms to the left:
12(7x+5)x-(13)=0
We multiply parentheses
84x^2+60x-13=0
a = 84; b = 60; c = -13;
Δ = b2-4ac
Δ = 602-4·84·(-13)
Δ = 7968
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{7968}=\sqrt{16*498}=\sqrt{16}*\sqrt{498}=4\sqrt{498}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-4\sqrt{498}}{2*84}=\frac{-60-4\sqrt{498}}{168} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+4\sqrt{498}}{2*84}=\frac{-60+4\sqrt{498}}{168} $
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