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(16-2x)(27-2x)=276
We move all terms to the left:
(16-2x)(27-2x)-(276)=0
We add all the numbers together, and all the variables
(-2x+16)(-2x+27)-276=0
We multiply parentheses ..
(+4x^2-54x-32x+432)-276=0
We get rid of parentheses
4x^2-54x-32x+432-276=0
We add all the numbers together, and all the variables
4x^2-86x+156=0
a = 4; b = -86; c = +156;
Δ = b2-4ac
Δ = -862-4·4·156
Δ = 4900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4900}=70$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-86)-70}{2*4}=\frac{16}{8} =2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-86)+70}{2*4}=\frac{156}{8} =19+1/2 $
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