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x+(x+2)+(x+4)+(x+6)=4x+12=212
We move all terms to the left:
x+(x+2)+(x+4)+(x+6)-(4x+12)=0
We get rid of parentheses
x+x+x+x-4x+2+4+6-12=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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