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(16+2x)(24+2x)=1008
We move all terms to the left:
(16+2x)(24+2x)-(1008)=0
We add all the numbers together, and all the variables
(2x+16)(2x+24)-1008=0
We multiply parentheses ..
(+4x^2+48x+32x+384)-1008=0
We get rid of parentheses
4x^2+48x+32x+384-1008=0
We add all the numbers together, and all the variables
4x^2+80x-624=0
a = 4; b = 80; c = -624;
Δ = b2-4ac
Δ = 802-4·4·(-624)
Δ = 16384
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{16384}=128$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(80)-128}{2*4}=\frac{-208}{8} =-26 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(80)+128}{2*4}=\frac{48}{8} =6 $
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