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(20+2x)(26+2x)=1672
We move all terms to the left:
(20+2x)(26+2x)-(1672)=0
We add all the numbers together, and all the variables
(2x+20)(2x+26)-1672=0
We multiply parentheses ..
(+4x^2+52x+40x+520)-1672=0
We get rid of parentheses
4x^2+52x+40x+520-1672=0
We add all the numbers together, and all the variables
4x^2+92x-1152=0
a = 4; b = 92; c = -1152;
Δ = b2-4ac
Δ = 922-4·4·(-1152)
Δ = 26896
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{26896}=164$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(92)-164}{2*4}=\frac{-256}{8} =-32 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(92)+164}{2*4}=\frac{72}{8} =9 $
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