(15q+13)(2q+3)=0

Solution for (15q+13)(2q+3)=0 equation:

(15q+13)(2q+3)=0

We multiply parentheses ..

(+30q^2+45q+26q+39)=0

We get rid of parentheses

30q^2+45q+26q+39=0

We add all the numbers together, and all the variables

30q^2+71q+39=0

a = 30; b = 71; c = +39;
Δ = b2-4ac
Δ = 712-4·30·39
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{361}=19$
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(71)-19}{2*30}=\frac{-90}{60}
=-1+1/2
$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(71)+19}{2*30}=\frac{-52}{60}
=-13/15
$