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(3x-135)+(1/2x+7)=180
We move all terms to the left:
(3x-135)+(1/2x+7)-(180)=0
Domain of the equation: 2x+7)!=0We get rid of parentheses
x∈R
3x+1/2x-135+7-180=0
We multiply all the terms by the denominator
3x*2x-135*2x+7*2x-180*2x+1=0
Wy multiply elements
6x^2-270x+14x-360x+1=0
We add all the numbers together, and all the variables
6x^2-616x+1=0
a = 6; b = -616; c = +1;
Δ = b2-4ac
Δ = -6162-4·6·1
Δ = 379432
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{379432}=\sqrt{4*94858}=\sqrt{4}*\sqrt{94858}=2\sqrt{94858}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-616)-2\sqrt{94858}}{2*6}=\frac{616-2\sqrt{94858}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-616)+2\sqrt{94858}}{2*6}=\frac{616+2\sqrt{94858}}{12} $
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