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(15+x)(20+x)=750
We move all terms to the left:
(15+x)(20+x)-(750)=0
We add all the numbers together, and all the variables
(x+15)(x+20)-750=0
We multiply parentheses ..
(+x^2+20x+15x+300)-750=0
We get rid of parentheses
x^2+20x+15x+300-750=0
We add all the numbers together, and all the variables
x^2+35x-450=0
a = 1; b = 35; c = -450;
Δ = b2-4ac
Δ = 352-4·1·(-450)
Δ = 3025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3025}=55$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-55}{2*1}=\frac{-90}{2} =-45 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+55}{2*1}=\frac{20}{2} =10 $
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