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(13/3)a=6
We move all terms to the left:
(13/3)a-(6)=0
Domain of the equation: 3)a!=0We add all the numbers together, and all the variables
a!=0/1
a!=0
a∈R
(+13/3)a-6=0
We multiply parentheses
13a^2-6=0
a = 13; b = 0; c = -6;
Δ = b2-4ac
Δ = 02-4·13·(-6)
Δ = 312
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{312}=\sqrt{4*78}=\sqrt{4}*\sqrt{78}=2\sqrt{78}$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{78}}{2*13}=\frac{0-2\sqrt{78}}{26} =-\frac{2\sqrt{78}}{26} =-\frac{\sqrt{78}}{13} $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{78}}{2*13}=\frac{0+2\sqrt{78}}{26} =\frac{2\sqrt{78}}{26} =\frac{\sqrt{78}}{13} $
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