36=4(y-3)+8y

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Solution for 36=4(y-3)+8y equation: 



36=4(y-3)+8y

We move all terms to the left:

36-(4(y-3)+8y)=0



We calculate terms in parentheses: -(4(y-3)+8y), so:

4(y-3)+8y

We add all the numbers together, and all the variables

8y+4(y-3)

We multiply parentheses

8y+4y-12

We add all the numbers together, and all the variables

12y-12

Back to the equation:

-(12y-12)



We get rid of parentheses

-12y+12+36=0

We add all the numbers together, and all the variables

-12y+48=0

We move all terms containing y to the left, all other terms to the right

-12y=-48

y=-48/-12

y=+4

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