(12x-36)+(7x+4)+(10x-20)=180

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Solution for (12x-36)+(7x+4)+(10x-20)=180 equation: 



(12x-36)+(7x+4)+(10x-20)=180

We move all terms to the left:

(12x-36)+(7x+4)+(10x-20)-(180)=0

We get rid of parentheses

12x+7x+10x-36+4-20-180=0

We add all the numbers together, and all the variables

29x-232=0

We move all terms containing x to the left, all other terms to the right

29x=232

x=232/29

x=8

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