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1/2(x-5)-2/3(5x-5)=5/12
We move all terms to the left:
1/2(x-5)-2/3(5x-5)-(5/12)=0
Domain of the equation: 2(x-5)!=0
x∈R
Domain of the equation: 3(5x-5)!=0We add all the numbers together, and all the variables
x∈R
1/2(x-5)-2/3(5x-5)-(+5/12)=0
We get rid of parentheses
1/2(x-5)-2/3(5x-5)-5/12=0
We calculate fractions
(36x5/(2(x-5)*3(5x-5)*12)+(-48xx/(2(x-5)*3(5x-5)*12)+(-30x^2x/(2(x-5)*3(5x-5)*12)=0
We calculate terms in parentheses: +(36x5/(2(x-5)*3(5x-5)*12)+(-48xx/(2(x-5)*3(5x-5)*12)+(-30x^2x/(2(x-5)*3(5x-5)*12), so:
36x5/(2(x-5)*3(5x-5)*12)+(-48xx/(2(x-5)*3(5x-5)*12)+(-30x^2x/(2(x-5)*3(5x-5)*12
We can not solve this equation
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