(12x-28)=(9x-77)

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Solution for (12x-28)=(9x-77) equation: 



(12x-28)=(9x-77)

We move all terms to the left:

(12x-28)-((9x-77))=0

We get rid of parentheses

12x-((9x-77))-28=0



We calculate terms in parentheses: -((9x-77)), so:

(9x-77)

We get rid of parentheses

9x-77

Back to the equation:

-(9x-77)



We get rid of parentheses

12x-9x+77-28=0

We add all the numbers together, and all the variables

3x+49=0

We move all terms containing x to the left, all other terms to the right

3x=-49

x=-49/3

x=-16+1/3

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