41-5x=2(1+4x)

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Solution for 41-5x=2(1+4x) equation: 



41-5x=2(1+4x)

We move all terms to the left:

41-5x-(2(1+4x))=0

We add all the numbers together, and all the variables

-5x-(2(4x+1))+41=0



We calculate terms in parentheses: -(2(4x+1)), so:

2(4x+1)

We multiply parentheses

8x+2

Back to the equation:

-(8x+2)



We get rid of parentheses

-5x-8x-2+41=0

We add all the numbers together, and all the variables

-13x+39=0

We move all terms containing x to the left, all other terms to the right

-13x=-39

x=-39/-13

x=+3

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