(12x+6(4x+3))/3=2(6x+4)-2

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Solution for (12x+6(4x+3))/3=2(6x+4)-2 equation: 



(12x+6(4x+3))/3=2(6x+4)-2

We move all terms to the left:

(12x+6(4x+3))/3-(2(6x+4)-2)=0

We multiply all the terms by the denominator


(12x+6(4x+3))-((2(6x+4)-2))*3=0



We calculate terms in parentheses: +(12x+6(4x+3)), so:

12x+6(4x+3)

We multiply parentheses

12x+24x+18

We add all the numbers together, and all the variables

36x+18

Back to the equation:

+(36x+18)



We get rid of parentheses

36x-((2(6x+4)-2))*3+18=0

We move all terms containing x to the left, all other terms to the right

36x-((2(6x+4)-2))*3=-18

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