9-2(a-3(a-4)-5)=1-5(a-2)

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Solution for 9-2(a-3(a-4)-5)=1-5(a-2) equation: 



9-2(a-3(a-4)-5)=1-5(a-2)

We move all terms to the left:

9-2(a-3(a-4)-5)-(1-5(a-2))=0



We calculate terms in parentheses: -(1-5(a-2)), so:

1-5(a-2)

determiningTheFunctionDomain
-5(a-2)+1

We multiply parentheses

-5a+10+1

We add all the numbers together, and all the variables

-5a+11

Back to the equation:

-(-5a+11)



We get rid of parentheses

-2(a-3(a-4)-5)+5a-11+9=0

We add all the numbers together, and all the variables

5a-2(a-3(a-4)-5)-2=0

We move all terms containing a to the left, all other terms to the right

5a-2(a-3(a-4)-5)=2

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