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(12-3z)/(-4)=-3+2z
We move all terms to the left:
(12-3z)/(-4)-(-3+2z)=0
We add all the numbers together, and all the variables
(-3z+12)/(-4)-(2z-3)=0
We get rid of parentheses
(-3z+12)/(-4)-2z+3=0
We multiply all the terms by the denominator
(-3z+12)-2z*(-4)+3*(-4)=0
We add all the numbers together, and all the variables
(-3z+12)-2z*(-4)-12=0
We multiply parentheses
(-3z+12)+8z-12=0
We get rid of parentheses
-3z+8z+12-12=0
We add all the numbers together, and all the variables
5z=0
z=0/5
z=0
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