(12-2x)(8-2x)=0

Solution for (12-2x)(8-2x)=0 equation:

(12-2x)(8-2x)=0

We add all the numbers together, and all the variables

(-2x+12)(-2x+8)=0

We multiply parentheses ..

(+4x^2-16x-24x+96)=0

We get rid of parentheses

4x^2-16x-24x+96=0

We add all the numbers together, and all the variables

4x^2-40x+96=0

a = 4; b = -40; c = +96;
Δ = b2-4ac
Δ = -402-4·4·96
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-40)-8}{2*4}=\frac{32}{8}
=4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-40)+8}{2*4}=\frac{48}{8}
=6
$