2y-22=7(y-6)

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Solution for 2y-22=7(y-6) equation: 



2y-22=7(y-6)

We move all terms to the left:

2y-22-(7(y-6))=0



We calculate terms in parentheses: -(7(y-6)), so:

7(y-6)

We multiply parentheses

7y-42

Back to the equation:

-(7y-42)



We get rid of parentheses

2y-7y+42-22=0

We add all the numbers together, and all the variables

-5y+20=0

We move all terms containing y to the left, all other terms to the right

-5y=-20

y=-20/-5

y=+4

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