(12+b)(12-b)=0

Solution for (12+b)(12-b)=0 equation:

Simplifying
(12 + b)(12 + -1b) = 0

Multiply (12 + b) * (12 + -1b)
(12(12 + -1b) + b(12 + -1b)) = 0
((12 * 12 + -1b * 12) + b(12 + -1b)) = 0
((144 + -12b) + b(12 + -1b)) = 0
(144 + -12b + (12 * b + -1b * b)) = 0
(144 + -12b + (12b + -1b2)) = 0

Combine like terms: -12b + 12b = 0
(144 + 0 + -1b2) = 0
(144 + -1b2) = 0

Solving
144 + -1b2 = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-144' to each side of the equation.
144 + -144 + -1b2 = 0 + -144

Combine like terms: 144 + -144 = 0
0 + -1b2 = 0 + -144
-1b2 = 0 + -144

Combine like terms: 0 + -144 = -144
-1b2 = -144

Divide each side by '-1'.
b2 = 144

Simplifying
b2 = 144

Take the square root of each side:
b = {-12, 12}