(2x+5)(2x-5)=0

Solution for (2x+5)(2x-5)=0 equation:

Simplifying
(2x + 5)(2x + -5) = 0

Reorder the terms:
(5 + 2x)(2x + -5) = 0

Reorder the terms:
(5 + 2x)(-5 + 2x) = 0

Multiply (5 + 2x) * (-5 + 2x)
(5(-5 + 2x) + 2x * (-5 + 2x)) = 0
((-5 * 5 + 2x * 5) + 2x * (-5 + 2x)) = 0
((-25 + 10x) + 2x * (-5 + 2x)) = 0
(-25 + 10x + (-5 * 2x + 2x * 2x)) = 0
(-25 + 10x + (-10x + 4x2)) = 0

Combine like terms: 10x + -10x = 0
(-25 + 0 + 4x2) = 0
(-25 + 4x2) = 0

Solving
-25 + 4x2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '25' to each side of the equation.
-25 + 25 + 4x2 = 0 + 25

Combine like terms: -25 + 25 = 0
0 + 4x2 = 0 + 25
4x2 = 0 + 25

Combine like terms: 0 + 25 = 25
4x2 = 25

Divide each side by '4'.
x2 = 6.25

Simplifying
x2 = 6.25

Take the square root of each side:
x = {-2.5, 2.5}