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(12+2x)(8+2x)=210
We move all terms to the left:
(12+2x)(8+2x)-(210)=0
We add all the numbers together, and all the variables
(2x+12)(2x+8)-210=0
We multiply parentheses ..
(+4x^2+16x+24x+96)-210=0
We get rid of parentheses
4x^2+16x+24x+96-210=0
We add all the numbers together, and all the variables
4x^2+40x-114=0
a = 4; b = 40; c = -114;
Δ = b2-4ac
Δ = 402-4·4·(-114)
Δ = 3424
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3424}=\sqrt{16*214}=\sqrt{16}*\sqrt{214}=4\sqrt{214}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(40)-4\sqrt{214}}{2*4}=\frac{-40-4\sqrt{214}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(40)+4\sqrt{214}}{2*4}=\frac{-40+4\sqrt{214}}{8} $
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