(11x-5)+(9x-3)+48=180

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Solution for (11x-5)+(9x-3)+48=180 equation: 



(11x-5)+(9x-3)+48=180

We move all terms to the left:

(11x-5)+(9x-3)+48-(180)=0

We add all the numbers together, and all the variables

(11x-5)+(9x-3)-132=0

We get rid of parentheses

11x+9x-5-3-132=0

We add all the numbers together, and all the variables

20x-140=0

We move all terms containing x to the left, all other terms to the right

20x=140

x=140/20

x=7

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