8(t+2)-3)t-4)=6(t-7)+8

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Solution for 8(t+2)-3)t-4)=6(t-7)+8 equation: 



8(t+2)-3)t-4)=6(t-7)+8

We move all terms to the left:

8(t+2)-3)t-4)-(6(t-7)+8)=0

We add all the numbers together, and all the variables

8(t+2)-3)t-4)-(6(t=0

We multiply parentheses

8t-3)t-4)-(6(t+16=0

We move all terms containing t to the left, all other terms to the right

8t-3)t-4)-(6(t=-16

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