(11x-2)+(19x+3)+(9x+1)=180

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Solution for (11x-2)+(19x+3)+(9x+1)=180 equation: 



(11x-2)+(19x+3)+(9x+1)=180

We move all terms to the left:

(11x-2)+(19x+3)+(9x+1)-(180)=0

We get rid of parentheses

11x+19x+9x-2+3+1-180=0

We add all the numbers together, and all the variables

39x-178=0

We move all terms containing x to the left, all other terms to the right

39x=178

x=178/39

x=4+22/39

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