-5(2y-12)+4y=3

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Solution for -5(2y-12)+4y=3 equation: 



-5(2y-12)+4y=3

We move all terms to the left:

-5(2y-12)+4y-(3)=0

We add all the numbers together, and all the variables

4y-5(2y-12)-3=0

We multiply parentheses

4y-10y+60-3=0

We add all the numbers together, and all the variables

-6y+57=0

We move all terms containing y to the left, all other terms to the right

-6y=-57

y=-57/-6

y=9+1/2

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