(11c+5)(6c-7)=0

Solution for (11c+5)(6c-7)=0 equation:

(11c+5)(6c-7)=0

We multiply parentheses ..

(+66c^2-77c+30c-35)=0

We get rid of parentheses

66c^2-77c+30c-35=0

We add all the numbers together, and all the variables

66c^2-47c-35=0

a = 66; b = -47; c = -35;
Δ = b2-4ac
Δ = -472-4·66·(-35)
Δ = 11449
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{11449}=107$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-47)-107}{2*66}=\frac{-60}{132}
=-5/11
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-47)+107}{2*66}=\frac{154}{132}
=1+1/6
$