3y+28=-5(y+4)

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Solution for 3y+28=-5(y+4) equation: 



3y+28=-5(y+4)

We move all terms to the left:

3y+28-(-5(y+4))=0



We calculate terms in parentheses: -(-5(y+4)), so:

-5(y+4)

We multiply parentheses

-5y-20

Back to the equation:

-(-5y-20)



We get rid of parentheses

3y+5y+20+28=0

We add all the numbers together, and all the variables

8y+48=0

We move all terms containing y to the left, all other terms to the right

8y=-48

y=-48/8

y=-6

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