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(11/3x)+(2/7)=(5/3x)
We move all terms to the left:
(11/3x)+(2/7)-((5/3x))=0
Domain of the equation: 3x)!=0
x!=0/1
x!=0
x∈R
Domain of the equation: 3x))!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+11/3x)-((+5/3x))+(+2/7)=0
We get rid of parentheses
11/3x-((+5/3x))+2/7=0
We calculate fractions
(-((+5*3x*7)/63x^2+54x^2/63x^2+231x/63x^2=0
We can not solve this equation
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