(11-k)/(3)=(3k-9)/(9)

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Solution for (11-k)/(3)=(3k-9)/(9) equation: 



(11-k)/(3)=(3k-9)/(9)

We move all terms to the left:

(11-k)/(3)-((3k-9)/(9))=0

We add all the numbers together, and all the variables

(-1k+11)/3-((3k-9)/9)=0

We calculate fractions


(-k)/()+(-((3k-9)*3)/()=0



We calculate terms in parentheses: +(-((3k-9)*3)/(), so:

-((3k-9)*3)/(

We multiply all the terms by the denominator


-((3k-9)*3)



We calculate terms in parentheses: -((3k-9)*3), so:

(3k-9)*3

We multiply parentheses

9k-27

Back to the equation:

-(9k-27)



We get rid of parentheses

-9k+27

Back to the equation:

+(-9k+27)



We add all the numbers together, and all the variables

(-1k)/()+(-9k+27)=0

We get rid of parentheses

(-1k)/()-9k+27=0

We multiply all the terms by the denominator


(-1k)-9k*()+27*()=0

We add all the numbers together, and all the variables

(-1k)-9k*()=0

We get rid of parentheses

-1k-9k*()=0

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