6(x-8)+2(3+x)=0

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Solution for 6(x-8)+2(3+x)=0 equation: 



6(x-8)+2(3+x)=0

We add all the numbers together, and all the variables

6(x-8)+2(x+3)=0

We multiply parentheses

6x+2x-48+6=0

We add all the numbers together, and all the variables

8x-42=0

We move all terms containing x to the left, all other terms to the right

8x=42

x=42/8

x=5+1/4

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