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(10x-7)(5x+2)=0
We multiply parentheses ..
(+50x^2+20x-35x-14)=0
We get rid of parentheses
50x^2+20x-35x-14=0
We add all the numbers together, and all the variables
50x^2-15x-14=0
a = 50; b = -15; c = -14;
Δ = b2-4ac
Δ = -152-4·50·(-14)
Δ = 3025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3025}=55$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-55}{2*50}=\frac{-40}{100} =-2/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+55}{2*50}=\frac{70}{100} =7/10 $
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