(10x-4)/6=(8x-20)/4

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Solution for (10x-4)/6=(8x-20)/4 equation: 



(10x-4)/6=(8x-20)/4

We move all terms to the left:

(10x-4)/6-((8x-20)/4)=0

We calculate fractions


10x/()+(-((8x-20)*6)/()=0



We calculate terms in parentheses: +(-((8x-20)*6)/(), so:

-((8x-20)*6)/(

We multiply all the terms by the denominator


-((8x-20)*6)



We calculate terms in parentheses: -((8x-20)*6), so:

(8x-20)*6

We multiply parentheses

48x-120

Back to the equation:

-(48x-120)



We get rid of parentheses

-48x+120

Back to the equation:

+(-48x+120)



We get rid of parentheses

10x/()-48x+120=0

We multiply all the terms by the denominator


10x-48x*()+120*()=0

We add all the numbers together, and all the variables

10x-48x*()=0

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