3-(x-3)=2+2(x+2)

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Solution for 3-(x-3)=2+2(x+2) equation: 



3-(x-3)=2+2(x+2)

We move all terms to the left:

3-(x-3)-(2+2(x+2))=0

We get rid of parentheses

-x-(2+2(x+2))+3+3=0



We calculate terms in parentheses: -(2+2(x+2)), so:

2+2(x+2)

determiningTheFunctionDomain
2(x+2)+2

We multiply parentheses

2x+4+2

We add all the numbers together, and all the variables

2x+6

Back to the equation:

-(2x+6)



We add all the numbers together, and all the variables

-1x-(2x+6)+6=0

We get rid of parentheses

-1x-2x-6+6=0

We add all the numbers together, and all the variables

-3x=0

x=0/-3

x=0

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