(10x-20)/5=10x+28

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Solution for (10x-20)/5=10x+28 equation: 



(10x-20)/5=10x+28

We move all terms to the left:

(10x-20)/5-(10x+28)=0

We get rid of parentheses

(10x-20)/5-10x-28=0

We multiply all the terms by the denominator


(10x-20)-10x*5-28*5=0

We add all the numbers together, and all the variables

(10x-20)-10x*5-140=0

Wy multiply elements

(10x-20)-50x-140=0

We get rid of parentheses

10x-50x-20-140=0

We add all the numbers together, and all the variables

-40x-160=0

We move all terms containing x to the left, all other terms to the right

-40x=160

x=160/-40

x=-4

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