(10x-18)=(3x+14)+(5x-2)

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Solution for (10x-18)=(3x+14)+(5x-2) equation: 



(10x-18)=(3x+14)+(5x-2)

We move all terms to the left:

(10x-18)-((3x+14)+(5x-2))=0

We get rid of parentheses

10x-((3x+14)+(5x-2))-18=0



We calculate terms in parentheses: -((3x+14)+(5x-2)), so:

(3x+14)+(5x-2)

We get rid of parentheses

3x+5x+14-2

We add all the numbers together, and all the variables

8x+12

Back to the equation:

-(8x+12)



We get rid of parentheses

10x-8x-12-18=0

We add all the numbers together, and all the variables

2x-30=0

We move all terms containing x to the left, all other terms to the right

2x=30

x=30/2

x=15

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