-10=2/3(3k-9)

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Solution for -10=2/3(3k-9) equation: 



-10=2/3(3k-9)

We move all terms to the left:

-10-(2/3(3k-9))=0



Domain of the equation: 3(3k-9))!=0

k∈R



We multiply all the terms by the denominator


-(2-10*3(3k-9))=0



We calculate terms in parentheses: -(2-10*3(3k-9)), so:

2-10*3(3k-9)

determiningTheFunctionDomain
-10*3(3k-9)+2

Wy multiply elements

-30k(3+2

Back to the equation:

-(-30k(3+2)



We add all the numbers together, and all the variables

-(-30k5=0

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