(10x+3)/(2x-1)=2

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Solution for (10x+3)/(2x-1)=2 equation: 



(10x+3)/(2x-1)=2

We move all terms to the left:

(10x+3)/(2x-1)-(2)=0



Domain of the equation: (2x-1)!=0

We move all terms containing x to the left, all other terms to the right

2x!=1

x!=1/2

x!=1/2

x∈R



We multiply all the terms by the denominator


(10x+3)-2*(2x-1)=0

We multiply parentheses

(10x+3)-4x+2=0

We get rid of parentheses

10x-4x+3+2=0

We add all the numbers together, and all the variables

6x+5=0

We move all terms containing x to the left, all other terms to the right

6x=-5

x=-5/6

x=-5/6

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