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(10x+2)(5x-5)=180
We move all terms to the left:
(10x+2)(5x-5)-(180)=0
We multiply parentheses ..
(+50x^2-50x+10x-10)-180=0
We get rid of parentheses
50x^2-50x+10x-10-180=0
We add all the numbers together, and all the variables
50x^2-40x-190=0
a = 50; b = -40; c = -190;
Δ = b2-4ac
Δ = -402-4·50·(-190)
Δ = 39600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{39600}=\sqrt{3600*11}=\sqrt{3600}*\sqrt{11}=60\sqrt{11}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-40)-60\sqrt{11}}{2*50}=\frac{40-60\sqrt{11}}{100} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-40)+60\sqrt{11}}{2*50}=\frac{40+60\sqrt{11}}{100} $
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