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(2x+5)(2x+4)=90
We move all terms to the left:
(2x+5)(2x+4)-(90)=0
We multiply parentheses ..
(+4x^2+8x+10x+20)-90=0
We get rid of parentheses
4x^2+8x+10x+20-90=0
We add all the numbers together, and all the variables
4x^2+18x-70=0
a = 4; b = 18; c = -70;
Δ = b2-4ac
Δ = 182-4·4·(-70)
Δ = 1444
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1444}=38$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-38}{2*4}=\frac{-56}{8} =-7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+38}{2*4}=\frac{20}{8} =2+1/2 $
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