(10x+1)(x-6)=0

Solution for (10x+1)(x-6)=0 equation:

(10x+1)(x-6)=0

We multiply parentheses ..

(+10x^2-60x+x-6)=0

We get rid of parentheses

10x^2-60x+x-6=0

We add all the numbers together, and all the variables

10x^2-59x-6=0

a = 10; b = -59; c = -6;
Δ = b2-4ac
Δ = -592-4·10·(-6)
Δ = 3721
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3721}=61$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-59)-61}{2*10}=\frac{-2}{20}
=-1/10
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-59)+61}{2*10}=\frac{120}{20}
=6
$