(10a-78)=(2a+2)

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Solution for (10a-78)=(2a+2) equation: 



(10a-78)=(2a+2)

We move all terms to the left:

(10a-78)-((2a+2))=0

We get rid of parentheses

10a-((2a+2))-78=0



We calculate terms in parentheses: -((2a+2)), so:

(2a+2)

We get rid of parentheses

2a+2

Back to the equation:

-(2a+2)



We get rid of parentheses

10a-2a-2-78=0

We add all the numbers together, and all the variables

8a-80=0

We move all terms containing a to the left, all other terms to the right

8a=80

a=80/8

a=10

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