(2z)=(z+59)

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Solution for (2z)=(z+59) equation: 



(2z)=(z+59)

We move all terms to the left:

(2z)-((z+59))=0



We calculate terms in parentheses: -((z+59)), so:

(z+59)

We get rid of parentheses

z+59

Back to the equation:

-(z+59)



We get rid of parentheses

2z-z-59=0

We add all the numbers together, and all the variables

z-59=0

We move all terms containing z to the left, all other terms to the right

z=59

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