(10-y)/3y2=0

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Solution for (10-y)/3y2=0 equation: 



(10-y)/3y^2=0



Domain of the equation: 3y^2!=0

y^2!=0/3

y^2!=√0

y!=0

y∈R



We add all the numbers together, and all the variables

(-1y+10)/3y^2=0

We multiply all the terms by the denominator


(-1y+10)=0

We get rid of parentheses

-1y+10=0

We move all terms containing y to the left, all other terms to the right

-y=-10

y=-10/-1

y=+10

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